One must first work out the pOH which can be determined from the concentration of the OH ion.
To do this you first have to calculate the concentration of the Ca(OH)2 and KOH in the new volume which would be 25ml (10ml +15ml). So C1V1 = C2V2 e.g 2.4*10^-6 * 10ml = C2 * 25ml. Then it's easy to work out C2.
After you have done that for both compounds times the Ca(OH)2 concentration by 2 because there are two moles of OH. Add the concentration of KOH which would be the concentration of the OH to the answer worked out before (OH concentration) and that would be the final concentration of OH.
Finally work out the pOH by using pOH= - Log [OH] then take 14 - pOH to obtain the pH, which is your answer.
Hope I helped in answering your question :)
The pH of the solution will be 11.08.
So, you're essentially mixing two solutions that contain strong bases, calcium hydroxide,
SIDE NOTE SInce you didn't specify what
Although calcium hydroxide is not very soluble in water, it is still considered a strong base because what does dissolve will dissocite completely to give
Notice that you get
You need to keep track of the number of moles of hydroxide ions that you add together. Potassium hydroxide dissociates completely in aqueous solution to give
This time, 1 mole of potassium hydroxide produces 1 mole of hydroxide ions.
So, you've got 1 mole of hydroxide ions for every mole of
Don't forget that the total volume of the final solution will be
You know how many moles of
Solve for pOH by using
The pH of the solution will be