How do you simplify #sqrt(9/8)*sqrt(7/6)#?

Question

1407 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-30T04:34:27

Simplify #sqrt(9/8) * sqrt(7/16)#.

#sqrt 9/sqrt8 * sqrt7/sqrt16# =

#3/(sqrt2sqrt4) * sqrt7/4# =

#3/(2sqrt 2) * sqrt 7/4# =

#(3sqrt 7)/(8sqrt 2)# =

Rationalize the denominator.

#(3sqrt 7)/(8sqrt 2) * (sqrt 2)/(sqrt 2)# =

#(3sqrt 14)/(8sqrt 4)# =

#(3sqrt 14)/(8*2)# =

#(3sqrt 14)/16#