Question

Question #2aff7

Answer 1

Remember `b^(-m) = 1/(b^m)`
`1/b^(-m) = b^m`
`b^m*b^n = b^(m+n)`
`b^p/b^q = b^ (p-q)`

So `(3^(-3/4)*3^(5/4))/3^(-1/4)`

`= (3^(5/4)*3^(1/4))/3^(3/4)`

`= 3^((5/4+1/4-3/4))`

`= 3^(3/4)`