# Question #0e2bc

May 2, 2015

Your reactants are acetic acid, $C {H}_{3} C O O H$, and sodium bicarbonate, $N a H C {O}_{3}$.

The reaction will actually take place in two steps. The first step will result in the formation of sodium acetate, $C {H}_{3} C O O N a$, and carbonic acid, ${H}_{2} C {O}_{3}$. This will be a double replacement reaction.

The carbonic acid will then undergo a decomposition reaction to produce carbond dioxide, $C {O}_{2}$, and water, ${H}_{2} O$.

$C {H}_{3} C O O {H}_{\left(a q\right)} + N a H C {O}_{3 \left(s\right)} \to C {H}_{3} C O O N {a}_{\left(a q\right)} + {\underbrace{{H}_{2} C {O}_{3 \left(a q\right)}}}_{\textcolor{b l u e}{C {O}_{2} + {H}_{2} O}}$

All in all, the reaction will look like this

$C {H}_{3} C O O {H}_{\left(a q\right)} + N a H C {O}_{3 \left(s\right)} \to C {H}_{3} C O O N {a}_{\left(a q\right)} + C {O}_{2 \left(g\right)} + {H}_{2} {O}_{\left(l\right)}$

This is actually the classic vinegar - baking soda reaction.