Question #c2e26

1 Answer
May 5, 2015

You can first write it into the general form #ax^2+bx+c=0#, by noving to the left #x+7#:
#4x^2-x+4-x-7=0# that becomes:
#4x^2-2x-3=0#
Now it is in the form: #ax^2+bx+c=0# with:
#a=4#
#b=-2#
#c=-3#
so you can use the quadratic formula:
#x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)#