Question

Question #cb97b

Answer 1

The energy of that respective photon will be `4.4 * 10^(-19)"J"`.

Start from the equation that connects energy and frequency

`E = h * nu`, where

`h` - Planck's constant, equal to `6.626 * 10^(-34)"J s"`;
`nu` - the frequency of the photon.

Since you were given the wavelength of the photon, you can rewrite the above equation like this

`nu = c/(lamda)`

`E = h * nu = h * c/(lamda)`, where

`c` - the speed of light, equal to `3.0 * 10^(8)"m s"^(-1)`;
`lamda` - the wavelength of the photon.

Plug your values into this equation and solve for `E`

`E = (6.626 * 10^(-34)"J"cancel("s") * 3.0 * 10^(8)cancel("m")cancel("s"^(-1)))/(4.5 * 10^(-7)cancel("m"))`

`E = color(green)(4.4 * 10^(-19)"J")`