# How do you solve (x+1)^2+2 = 7 ?

May 12, 2015

First subtract 2 from both sides to get:

${\left(x + 1\right)}^{2} = 5$

Take the square root of both sides, allowing either possible sign:

$x + 1 = \pm \sqrt{5}$

Subtract 1 from both sides to get:

$x = - 1 \pm \sqrt{5}$