What volume of a #"2.0 M"# stock solution is required to produce #"500 mL"# of a #"0.49 M"# solution?

1 Answer
Meave60
May 20, 2015

The volume of the stock solution needed is #"0.1 L"# or #"100 mL"# .

Use the dilution equation #"M"_1"V"_1"##=##"M"_2"V"_2"#, where #"M"# is the concentration of a solution in #"mol/L"#, and #"V"# is volume in liters, and #1# is the concentrated conditions, and #2# is the diluted conditions.

Known:
#"M"_1=2.0"mol/L"#
#"M"_2=0.49"mol/L"#
#"V"_2=500"mL"=0.5"L"#

Unknown:
#"V"_1"#

Solution:

#"V"_1=("M"_2"V"_2)/("M"_1)=(0.49 cancel"mol/L" * 0.5"L")/(2.0 cancel"mol/L")=0.1 "L"="100 mL"# (rounded to one significant figure due to one significant figure)

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