Question #8c623

1 Answer
Jun 9, 2015

Answer:

1) #o->p#
Av(speed)#=20m/s#
Av(velocity)#=20 m/s#
2) #o->p->o#
Av(speed)#=20m/s#
Av(velocity)#=0 m/s#

Explanation:

I considered only the distance op (I didn't use oq).
The average velocity is the change of position #x#, indicated as #Deltax# (known as displacement), divided by the corresponding change in time #Deltat#.
#v_(av)=(Deltax)/(Deltay)=(x_f-x_i)/(t_f-t_i)#
Where #x_i# is the position at #o# that I considered the origin #x_1=0#.

The average speed #s# is a little bit more subtle...it is the total distance travelled, #d#, divided by the time needed.
#s_(av)=d/t#

So you get:
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