Question

Question #8c623

Answer 1

1) `o->p`
Av(speed)`=20m/s`
Av(velocity)`=20 m/s`
2) `o->p->o`
Av(speed)`=20m/s`
Av(velocity)`=0 m/s`

Explanation:

I considered only the distance op (I didn't use oq).
The average velocity is the change of position `x`, indicated as `Deltax` (known as displacement), divided by the corresponding change in time `Deltat`.
`v_(av)=(Deltax)/(Deltay)=(x_f-x_i)/(t_f-t_i)`
Where `x_i` is the position at `o` that I considered the origin `x_1=0`.

The average speed `s` is a little bit more subtle...it is the total distance travelled, `d`, divided by the time needed.
`s_(av)=d/t`

So you get: