Question #1e6f1

1 Answer
Daniel L.
Jun 21, 2015

The solution is : #x=e vv x=1/e#

Explanation:

The logarythms have different bases, so first you have to change base using formula:

#log_ax=log_ba/log_bx#

In this case we get:

#log_ex-1/log_ex=0#

#(log_ex)^2-1=0#

#(log_ex-1)(log_ex+1)=0#

#log_ex-1=0 vv log_ex+1=0#

#log_ex=1 vv log_ex=-1#

#x=e vv x=1/e#

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