Question

Question #0a95e

Answer 1

The answer is B

Explanation:

Relative atomic mass of `Al=27` and `Cl=35.5`
To form `AlCl_3` you need these in the ratio:

`(m(Cl))/(m(Al))= (3*35.5)/(1*27)=106.5/27->`

`m(Cl)=106.5/27*m(Al)=106.5/27*13.5=53.2g`

The mass of the `AlCl_3`
`m(AlCl_3)=13.5+53.2=66.7g`