The answer is E) All the above ions are present in the complete ionic equation.
In your case, lead (II) nitrate and potassium iodide are both soluble compounds that exist as ions in solution
When you mix two solutions that contain these ions together, lead iodide, a yellow precipitate, is formed.
The ions that don't become a part of the insoluble solid will remain in solution and act as spectator ions.
So, if you put all this together, you'll get
As you can see, all the ions listed in your question are a part of the complete ionic equation.
The net ionic equation will be