Question #b54e2

1 Answer
Jul 17, 2015

Answer:

#K_c=([HI]^(2))/([H_2][I_2])#

Where [ ] represents concentrations at equilibrium.

Explanation:

In general for a reaction:

#aA+bBrightleftharpoonscC+dD#

  • the expression for #K_c# is given by:

#K_c=([C]^(c)[D]^(d))/([A]^(a)[B]^(b))#

Where [ ] represents concentration of the species at equilibrium.

If we apply the general rule to this specific reaction:

#H_(2(g))+I_(2(g))rightleftharpoons2HI_((g))#

we get:

#K_c=([HI]^(2))/([H_2][I_2])#

Note that whenever you quote a value for #K_c# you must also state the temperature as well.