Question #b85b6

1 Answer

Solve a fourth-degree polynomial equation.

Explanation:

#sqrt{3 + x} + sqrt{2x - 1} = 5x \ge 1/2#

First, #x \ge 1/10#

Second, #sqrt{3 + x} = 5x - sqrt{2x - 1}#

#3 + x = (5x - sqrt{2x - 1})^2#

#3 + x = 25x^2 + 2x - 1 - 10xsqrt{2x - 1}#

#10xsqrt{2x - 1} = 25x^2 + x - 4#

#100x^2{2x - 1} = (25x^2 + x - 4)^2#

#200x^3 - 100x^2 = 625x^4 + x^2 + 16 + 50x^3 - 200x^2 - 8x#

#0 = 625x^4 - 150x^3 -99 x^2 - 8x + 16#

Here you can use Newton. Or test the fractions #n/d#

where #d# divides #625# and #n# divides #16#.

https://en.wikipedia.org/wiki/Newton%27s_method