Here's how you can figure these out.
This will help ypu determine which compound will exist as ions in aqueous solution and which as molecules.
In your case, you have two soluble ionic compounds, sodium sulfite,
This means that barium sulfite will not exist as ions in solution. So, let's take these equations one by one
- Molecular equation
To write the molecular equation, simply use the compounds as they are written - but don't forget to include state symbols!
- Complete ionic equation
To write the complete ionic equation you need to break all the ionic compounds into cations and anions. All ions that take part in the reaction are included.
- Net ionic equation
This time you need to remove spectator ions, which are ions that are present on both sides of the equation.
In your case, the sodium cations and the acetate anions will not appear in the net ionic equation.
This is equivalent to