Question

Question #651d1

Answer 1

Density: `"0.52 kg/m"""^3`

Explanation:

So, you know that you're dealing with an object that has a certain mass and a certain volume.

You weigh the object and determine that it has a mass of 22 kg. Likewise, you measure the volume of the object and determine that it occupies `"42 m"""^3`.

Density is defined as mass per unit of volume. In other words, density tells you what the mass of one unit of volume is for a given object.

SInce you measured the volume in cubic meters, the unit of volume will be `"1 m"""^3`.

So, to get the object's density, you need to determine what the mass of `"1 m"""^3` is. To do that, use the fact that you know what the mass of `"42 m"""^3` is

`1cancel("m"""^3) * "22 kg"/(42cancel("m"""^3)) = "0.5238 kg"`

If one cubic meter has a mass of 0.5238 kg, then the object's density will be

`rho = "0.5238 kg"/("1 m"""^3) = "0.5238 kg/m"""^3`

Rounded to two sig figs, the number of sig figs you used for your two measurements, the answer will be

`rho = color(green)("0.52 kg/m"""^3)`