Question #e1fc4

1 Answer
Jul 24, 2015

dy/dx=(2ln2)4^sec(x)sec(x)tan(x)

Explanation:

Lets say we want to find the derivative of 2^x.
It is (ln2)2^x

In the problem we do the same thing and remember
to use the chain rule.

dy/dx=(ln4)4^sec(x)d/dx[sec(x)]

dy/dx=(ln2^2)4^sec(x)sec(x)tan(x)

dy/dx=(2ln2)4^sec(x)sec(x)tan(x)