# Question b8fb3

Aug 1, 2015

Check the oxidation numbers — in a disproportionation reaction the same substance is simultaneously oxidized and reduced.

#### Explanation:

An example is the disproportionation of chlorine in basic solution.

The unbalanced equation is

$\text{Cl"_2 + "OH"^(-) → "Cl"^(-) + "OCl"^(-) + "H"_2"O}$.

If you check the oxidation numbers, you will find

 stackrel(color(blue)(0))("Cl")_2 + "OH"^(-) → stackrel(color(blue)(-1))("Cl")""^(-) + "O" stackrel(color(blue)(+1))("Cl")""^(-) + "H"_2"O"#.

$\text{Cl}$ has been oxidized from $\text{ON=0}$ to $\text{ON=+1}$ and reduced from $\text{ON=0}$ to $\text{ON = -1}$.

Some other examples from Socratic are the disproportionation of