# Question #497d1

##### 2 Answers

#### Explanation:

We know that the change in

Therefore, as a linear approximation, we may use:

Of course, you may also calculate the exact increase by substitution of

Of course, this is very close to the approximation we get using the differential.

The amount of the increase is:

The proportion or percent increase is:

#### Explanation:

When the radius increases

# = 1.331(4/3pir^3) = 1.331V_1#

The amount of the increase is:

The proportion or percent increase is: