Suppose #x# varies directly as both #y# and #z# (and #y# and #z# vary inversely with each other. If #x=6# when #y=6# and #z=123#, what is the value of #z# when #x=7# and #y-8#?

1 Answer
Aug 26, 2015

#z= 107 5/8#

Explanation:

For either "y directly as x and inversely as z" or "z directly as x and inversely as y":

#(y*z)/x = c# where #c# is a constant.

We are told #(x,y,z)=(6,6,123)# is a solution to this equation.

So
#color(white)("XXX")(cancel(6)*123)/cancel(6) = c#

If #x=7# and #y=8#, we have
#color(white)("XXXX")(8*z)/7 = 123#
#rArrcolor(white)("XXXXXXXXXXX")z = 861/8 = 107 5/8#