Question #1f618

1 Answer
Aug 26, 2015

cot#(-pi/4)=-cot(pi/4)#
sec#((7pi)/6)=sec(pi+pi/6)=-sec(pi/6)#

Explanation:

Angle #-pi/4# is in the IVth quadrant, where cot is negative,

hence cot#(-pi/4)=-cot(pi/4)#

Angle#((7pi)/6)# is in the IIIrd quadrant where cosine and hence sec is negative. This makes sec#((7pi)/6)=sec(pi+pi/6)=-sec(pi/6)#