# Question #a6330

##### 1 Answer

#### Answer:

The sheet of lead has a thickness of

#### Explanation:

You can think of your sheet of lead as being a *rectangular prism* with a very, very small thichness,

#color(blue)(V = l * w * h)#

The idea here is that you can determine the volume of the sheet of lead by using its density and its mass. Since density is defined as mass per unit of volume, you can use the known mass to figure out the volume that much lead would occupy.

#color(blue)(rho = m/V implies V = m/(rho)#

In your case, you have

#V = (0.627color(red)(cancel(color(black)("g"))))/(11.34color(red)(cancel(color(black)("g")))/"cm"^3) = "0.05529 cm"""^3#

This means that the thickness of the sheet will be

#V = l * w * h implies h = V/(l * w)#

#h = ("0.05529 cm"^color(red)(cancel(color(black)(3))))/(15.5color(red)(cancel(color(black)("cm"))) * 23.0color(red)(cancel(color(black)("cm")))) = color(green)(1.55 * 10^(-4)"cm")#