# Question #e55ba

Nov 4, 2015

141.86 MJ/kg or about 3 eV per molecule of H2

#### Explanation:

$\frac{142 \cdot {10}^{6}}{497.5 \cdot a v o g a \mathrm{dr} o , c o n s \tan t}$
$= 4.73974 \cdot {10}^{- 19}$

$\frac{4.73974}{1.6022} = 2.96 e V$ OR about 3 eV

I put as electron volt because it is easier to compare with hydrogen energy level (of electron shells). Refer to http://hyperphysics.phy-astr.gsu.edu/hbase/hyde.html