Question #016df

1 Answer
bp
Sep 16, 2015

#(x-5)^5= x^5 +5x^4 (-5) +10x^3 (-5)^2 +10x^2 (-5)^3+ 5x(-5)^4 +y^5#

Explanation:

In the Pascal triangle , the sixth row has the coefficients of the terms starting with #x^5 y^0# and ending with # x^0 y^5# in the expansion of #(x+y)^5#

If -5 is plugged in for y, expansion of #(x-5)^5# would roll out.

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