# What is the Lewis structure of ozone?

##### 1 Answer
Sep 26, 2015

$18$ ${e}^{-}$, to distribute around 3 atoms of oxygen. VSEPR would predict a bent structure, a formally positive central atom, and a formally negative terminal atom.

#### Explanation:

$O = \stackrel{+}{O} - {O}^{-}$. From left to right, around each $O$ atom there are 6, 5, and 7 valence electrons, resulting in formal charges of $0$, $+ 1$, and $- 1$ respectively. Of course, I can draw the resonance structure with the negative charge on the LH $O$ atom. Because there are 3 regions of electron density around the central $O$ atom, (the double bond, the lone pair, and the single bond), we would predict a bent structure, with an $O - O - O$ bond angle of a bit less than ${120}^{\circ}$ around the central oxygen atom.

Here is a link that may help. (I assume it's public domain!).