# Question #14092

Sep 27, 2015

The answer is 8 $p$ orbitals.
The electron configuration of Germanium is: $\left[A r\right] 3 {d}^{10} 4 {s}^{2} 4 {p}^{2}$
The electrons on $p$ orbitals: $2 {p}^{6} , 3 {p}^{6} , 4 {p}^{2}$ which makes it a total of 14 electrons.
Therefore, 6 electrons occupy the 3 orbitals of the subshell $2 p$, another 6 electrons occupy the 3 orbitals of the subshell $3 p$ and 2 electrons occupy only 2 orbitals of the subshell $4 p$, which makes it a total of 8 $p$ orbitals .