How many moles are in #"24.65 g AlCl"_3"#?

1 Answer
Sep 30, 2015

There are #0.1849# moles of #"AlCl"_3"# in #24.65"g"#.

Explanation:

In order to determine the number of moles that are in #24.65"g"# of aluminum chloride #("AlCl"_3")#, you must know the mass of one mole of #"AlCl"_3"#, which is called its molar mass. You can do that by multiplying the subscript for each element times its atomic weight in grams/mol (from the periodic table), and adding them.

Molar Mass #"AlCl"_3"#

#(1xx26.982"g/mol Al")+(3xx35.45"g/mol Cl")=133.342"g/mol"#

Number of Moles in #24.65"g AlCl"_3"#

Divide the given mass of aluminum chloride by its molar mass.

#(24.65color(red)cancel(color(black)("g")) "AlCl"_3)/(133.342color(red)cancel(color(black)("g"))/"mol") ="0.1849 mol AgCl"_3#