# Question #48338

##### 2 Answers

1.52 mols of NO2.

#### Explanation:

So EqK=3.2 and let x be the NO2 amount.

So 3.2= (1.2)(1.2) / (2.6-1.2)(x)

And now solve for x..

You will arrive at x=0.3214...

Add 1.2 as it the amount of the product needed, so..

1.2+0.3214...=1.52 mols. Correct to 3 significant figures.

We will need

#### Explanation:

We will solve this question through ICE table.

Let us write the equilibrium and list the initial, change and concentrations at equilibrium.

We will assume 1 litre volume so we can calculate the concentrations.

The expression of

Replace the equilibrium concentrations by their values in the expression of

Solving for

Therefore, we will need