# Question #c7c7e

##### 1 Answer

The answer is **(d)**.

#### Explanation:

Once again, start by identifying which energy level, and implicitly *principal quantum number*,

This time, you're dealing with the fourth energy level,

You already know that the number of orbitals thatcan be found in each energy level is given by the equation

#"no. of orbitals" = n^2#

In your case, the fourth energy level will contain

#n = 4 implies "no. of orbitals" = 4^2 = 16#

The number of subshells is given by the principal quantum number.

#"no. of subshells" = n#

In your case, the fourth energy level will have

#"no. of subshells" = 4#

subshells, each containing

one 4s-orbitalthree 4p-orbitalsfive 4d-orbitalsseven 4f-orbitals

Now, how about the number of electrons?

Well, each orbital can hold a maximum of **two electrons**, one having spin-up and one having spin-down.

This means that the maximum number of electrons a given *shell*, or energy level, can have is equal to

#"no. of electrons" = 2n^2#

In your case, the fourth energy shell will can hold a maximum of

#"no. of electrons" = 2 * 4^2 = "32 e"^(-)#

So, as a conclusion, all three options are corresct, which implies that the answer will be **(d)**.