Question

Question #444cf

Answer 1

The reaction produces sodium carbonate, water, and carbon dioxide.

Explanation:

Sulfuric acid, `"H"_2"SO"_4`, will react with sodium carbonate, `"Na"_2"CO"_3`, to form sodium sulfate, `"Na"_2"SO"_4`, and carbonic acid, `"H"_2"CO"_3`.

In aqueous solution, carbonic acid actually exists in equilibrium with water and carbon dioxide, `"CO"_2`.

`"H"_2"CO"_text(3(aq]) rightleftharpoons "H"_2"O"_text((l]) + "CO"_text(2(aq])`

The balanced chemical equation for this reaction will looks like this

`"H"_2"SO"_text(4(aq]) + "Na"_2"CO"_text(3(s]) -> "Na"_2"SO"_text(4(aq]) + overbrace("H"_2"CO"_text(3(aq]))^(color(blue)("H"_2"O" + "CO"_2))`

The reaction can thus be written as

`"H"_2"SO"_text(4(aq]) + "Na"_2"CO"_text(3(s]) -> "Na"_2"SO"_text(4(aq]) + "H"_2"O"_text((l]) + "CO"_text(2(g]) uarr`

The carbon dioxide will bubble out of solution.