# Question 444cf

Oct 18, 2015

The reaction produces sodium carbonate, water, and carbon dioxide.

#### Explanation:

Sulfuric acid, ${\text{H"_2"SO}}_{4}$, will react with sodium carbonate, ${\text{Na"_2"CO}}_{3}$, to form sodium sulfate, ${\text{Na"_2"SO}}_{4}$, and carbonic acid, ${\text{H"_2"CO}}_{3}$.

In aqueous solution, carbonic acid actually exists in equilibrium with water and carbon dioxide, ${\text{CO}}_{2}$.

${\text{H"_2"CO"_text(3(aq]) rightleftharpoons "H"_2"O"_text((l]) + "CO}}_{\textrm{2 \left(a q\right]}}$

The balanced chemical equation for this reaction will looks like this

"H"_2"SO"_text(4(aq]) + "Na"_2"CO"_text(3(s]) -> "Na"_2"SO"_text(4(aq]) + overbrace("H"_2"CO"_text(3(aq]))^(color(blue)("H"_2"O" + "CO"_2))#

The reaction can thus be written as

${\text{H"_2"SO"_text(4(aq]) + "Na"_2"CO"_text(3(s]) -> "Na"_2"SO"_text(4(aq]) + "H"_2"O"_text((l]) + "CO}}_{\textrm{2 \left(g\right]}} \uparrow$

The carbon dioxide will bubble out of solution.