Question #5f4c9

1 Answer
Oct 22, 2015

#0.33"m"^3#

Explanation:

Since we can assume no change in pressure we can write:

#V_1/T_1=V_2/T_2#

#:.V_2=(V_1xxT_2)/(T_1)#

#V_2=(0.2xx553)/(333)#

#V_2=0.33"m"^3#

So we can see that there is an expected increase in volume if the temperature is raised at constant pressure.