# Question #7d62e

Oct 27, 2015

Assuming $15 , 000 c {m}^{3}$ of wood I got: $12 , 750 g$

#### Explanation:

Kate, remember that you need to include the units as well!
For example you have a volume of $15000$....$c {m}^{3}$?

You may use a table to find the DENSITY of your material (basically how much stuff fits into a given volume of this stuff); these tables can be found in textbooks, websites...as for example:

Density tells you the amount of mass in grams that fits into a volume of $1 c {m}^{3}$....for wood $0.85 \frac{g}{c {m}^{3}}$

So: $\text{density"="mass"/"volume}$ and rearranging:

$\text{mass"="density"xx"volume}$

If you have $15000 c {m}^{3}$ of wood then:

$\text{mass} = 0.85 \times 15000 = 12 , 750 g$
If you have different types of wood (cedar, fir, pine...etc) you can change the corresponding value of density and evaluate the new value of mass.