# Question #663d2

##### 1 Answer

Oct 27, 2015

#### Answer:

"Plug in" the two limits of your answer to check the interval. They do NOT match the problem criteria.

#### Explanation:

The final answer will be in the form you provided, but the values on the upper and lower limits must match those of the problem (0 and 1/2).

Substituting your values into the inequality:

(2(2)+4)^-1 = 1/8

and

(2(1)+4)^-1 = 1/6 do not span the inequality given.

You must solve it for the limits:

(2(x1)+4)^-1 = 0

and

(2(x2)+4)^-1 = 1/2

THEN you will have the range BETWEEN which the 'x' must be to satisfy the inequality. x1 < x < x2