Question #663d2

1 Answer
Oct 27, 2015

"Plug in" the two limits of your answer to check the interval. They do NOT match the problem criteria.

Explanation:

The final answer will be in the form you provided, but the values on the upper and lower limits must match those of the problem (0 and 1/2).
Substituting your values into the inequality:

(2(2)+4)^-1 = 1/8
and
(2(1)+4)^-1 = 1/6 do not span the inequality given.

You must solve it for the limits:
(2(x1)+4)^-1 = 0
and
(2(x2)+4)^-1 = 1/2

THEN you will have the range BETWEEN which the 'x' must be to satisfy the inequality. x1 < x < x2