# Question #b4e13

Oct 29, 2015

$2 \frac{m}{s} ^ 2$

#### Explanation:

For uniform circular motion the acceleration ($a$) can be calculated as a function of the velocity ($v$) and the radius ($r$).
$a = {v}^{2} / r$
The mass of the object is not needed in this calculation.
$a = {\left(1 \frac{m}{s}\right)}^{2} / \left(0.5 m\right)$
$a = 2 \frac{m}{s} ^ 2$

If you wanted to calculate the force required to maintain this motion, then you only need to know that $F = m a$. This mass in this case is $0.010 k g$.
$F = 0.010 \cdot 2 = 0.02 N$