What is the oxidation number of the metal in #"manganate ion"#, #MnO_4^(2-)#?
This is the manganate ion, where manganese has a
The oxdiation number of manganese in the anion
The first thing you need to realize is there are two bonds in this formula: the ionic bond between
With this kind of substances, it would be helpful if you separate the ions first since it would break down your equation into a more simpler one.
Now that you separated the ions, you can safely ignore the ammonium ion for the time being, as it would not affect your calculations for the oxidation state of
Thus we have the equation:
Therefore, the oxidation state of
Still in doubt? Let's try solving
[(+1) (2)] +
Same answer. :)