# Question #3ea48

Nov 14, 2015

$794.2 \text{m}$

#### Explanation:

The expression for range is :

$d = \frac{v \cos \theta}{g} \left(v \sin \theta + \sqrt{{\left(v \sin \theta\right)}^{2} + 2 g {y}_{0}}\right)$

${y}_{0}$ is the height of launch which, in this case, is $114 \text{m}$.

$\therefore d = \frac{90 \times 0.92}{9.8} \left(90 \times 0.39 + \sqrt{{\left(90 \times 0.39\right)}^{2} + \left(2 \times 9.8 \times 114\right)}\right)$

$d = 8.449 \left(35.1 + \sqrt{1236 + 2234.4}\right)$

$d = 794.2 \text{m}$