Question

Which element is oxidized and which is reduced in the reaction below?

`"3SnO"_3^"2-" + "Xe" + "OH"^"-" → "HXeO"_4^"-" + "3SnO"_2^"2-"`

Answer 1

See below.

Explanation:

`3stackrelcolor(blue)(+4)("Sn")stackrelcolor(blue)(-2)("O")_3color(white)(l)^(2-) + stackrelcolor(blue)(0)("Xe") + stackrelcolor(blue)(-2)("O")stackrelcolor(blue)(+1)("H")color(white)(l)^(-) → stackrelcolor(blue)(+1)("H")stackrelcolor(blue)(+6)("Xe")stackrelcolor(blue)(-2)("O")color(white)(l)_4^(-) + 3stackrelcolor(blue)(+2)("Sn")stackrelcolor(blue)(-2)("O")_2color(white)(l)^(2-)`

`"Sn"` is reduced: +4 → +2
`"Xe"` is oxidized: 0 → +6

Tin is the element reduced.
Xenon is the element oxidized.