What is the coordination number of cobalt in the #[Co(en)_2Br_2]^+# complex?
First thing first, if you're dealing with the dibromobis(ethylenediamine) cobalt(III) complex ion,
The charge of the chloride anion is
I think you could get cobalt in its
So my guess is that you're either dealing with
Anyway, this doesn't actually matter for finding the coordination number of cobalt.
As you know, the coordination number of an atom is determined by counting the number of other atoms to which it is bonded. Remember, single, double, or triple bonds have the same significance here.
So, take a look at the dibromobis(ethylenediamine) cobalt(III) ion. The central cobalt atom is bonded to
- two ethylenediamine molecules ,
- two bromide anions,
Now, it's important to realize that ethylenediamine is a bidentate ligand, which means that it uses two donor atoms to bind to the central cobalt atom.
More specifically, these donor atoms are the two nitrogen atoms
This means that the central cobalt atom will actually be bonded to a total of six atoms
- two nitrogen atoms from the first ethylenediamine molecule
- two nitrogen atoms from the second ethylenediamine molecule
- two bromine atoms
Therefore, the coordination number of cobalt in the
The coordination number of
Ethylenediamine is a bidentate ligand; it has 2 donor atoms to coordinate to the metal centre in a 5-membered chelate ring. Note that this (I presume) is a