# Question #a2ebd

Jan 27, 2016

$1 \frac{g}{c {m}^{3}}$

#### Explanation:

The density of a substance is its mass per unit volume $\left(\rho = \frac{m}{V}\right)$ hence it is constant regardless of the given mass or volume. It however varies with temperature and pressure but the differences are usually negligible in solids and liquids.

In the case of pure water, according to this website (link shown below) the densities of water in different selected temperatures are as follow:

• 0 degrees (solid) -> $\rho = 0.9150 \frac{g}{c {m}^{3}}$
• 0 degrees (liquid) -> $\rho = 0.9999 \frac{g}{c {m}^{3}}$
• 4 degrees -> $\rho = 1.0000 \frac{g}{c {m}^{3}}$
• 20 degrees -> $\rho = 0.9882 \frac{g}{c {m}^{3}}$
• 100 degrees (gas) -> $\rho = 0.0006 \frac{g}{c {m}^{3}}$

temperature is in degree Celcius
density shown is in $\frac{g}{c} {m}^{3}$

Note that at 4 degrees onwards, the density of pure water approaches 0. Specifically it follows this trend:

Sources:

Density Table

Graph