Question #79779

1 Answer
Bdub
Mar 8, 2016

#sin(3theta)=sin(2theta+theta)=sin2thetacos theta+cos2theta sintheta#
#cos(3theta)=cos(2theta+theta)=cos(2theta)costheta-sin(2thetasintheta)#
#tan(3theta)=tan(2theta+theta)=(tan(2theta)+tantheta)/(1-tan(2theta)(tantheta))#

Explanation:

#sin(3theta)=sin(2theta+theta)=sin2thetacos theta+cos2theta sintheta#
#cos(3theta)=cos(2theta+theta)=cos(2theta)costheta-sin(2thetasintheta)#
#tan(3theta)=tan(2theta+theta)=(tan(2theta)+tantheta)/(1-tan(2theta)(tantheta))#
Note you can simplify the double angles by using the appropriate double angle formula to dissolve it

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