What is the exact value of #sin 65^@# ?

1 Answer
Jun 23, 2017

There is no exact formula for #sin 65^@# without using trigonometric or related functions.

Explanation:

Unfortunately, #65^@# is an angle for which you cannot find the exact value of #sin theta#.

For angles which are a whole number of degrees, exact formulae can be found if and only if the angle is a multiple of #3^@#.

Note that we have exact values:

#sin 45^@ = cos 45^@ = sqrt(2)/2#

#sin 30^@ = 1/2#

#cos 30^@ = sqrt(3)/2#

Hence we can use the difference formulae to find:

#sin 15^@ = 1/4(sqrt(6)-sqrt(2))#

#cos 15^@ = 1/4(sqrt(6)+sqrt(2))#

In addition, by looking at the regular pentagon, we can find:

#sin 18^@ = 1/4(sqrt(5)-1)#

#cos 18^@ = 1/4 sqrt(10+2sqrt(5))#

See https://socratic.org/s/aFZNCmPD for details.

I won't multiply it out, but then we can use the difference formulae again to find exact formulae:

#sin 3^@ = sin 18^@ cos 15^@ - cos 18^@ sin 15^@#

#cos 3^@ = cos 18^@ cos 15^@ + sin 18^@ sin 15^@#

From these values you can find trigonometric values for any multiple of #3^@#.

To get values for #sin 1^@#, #cos 1^@# or any other whole number of degrees that is not a multiple of #3# involves taking the cube root of a complex number. You can certainly express it in that form, but it tells you nothing substantial: To find the formula in terms of real numbers will involve trigonometric functions again.