Question

Question #d5e47

Answer 1

`3030kJ`

Explanation:

Your method is 100% correct, but you made a small calculation error in converting the lb to g, by a factor of 10, resulting in you final answer being out by a factor of 10.

The amount of energy required to melt `1kg` of ice at `0^@C` is equal to the specific latent heat of fusion for ice and has value `L_f=334kJ//kg`.

So for `20xx0.4536=9.072kg`, we get that energy required to melt it is
`W=mL_f=9.072kgxx334000J//kg`

`=3.03MJ`

`=3030kJ`