Question

Question #90cca

Answer 1

`3xx10^(-7)"m"`

Explanation:

The relationship between speed, wavelength and frequency for a wave is given by:

`v=fxxlambda`

`v` is the velocity

`f` is the frequency

`lambda` is the wavelength

In the case of electromagnetic radiation the velocity is equal to `c`, the speed of light, which I will take to be `3xx10^8"m/s"`

`:.lambda=c/f=(3xx10^8)/(10^(15)`

`lambda=3xx10^(-7)"m"`

Planck's Constant `h`, which is given in the question is irrelevant.

You would use this if you want to find the energy of the photon given by :

`E=hf`