What is the concentration of chloride ion made from an #80*mL# volume of #0.125*mol*L^-1# #CaCl_2(aq)# that is diluted to a #100*mL# volume?

1 Answer
Jan 26, 2016

Answer:

#[Cl^-]# #=# #("Moles of chloride ion")/("Volume of solution")#

Explanation:

#"Moles of chloride"/"Volume of solution"#

We note that in the calcium chloride solution, each equiv calcium chloride contributes 2 equiv halide ion:

#[Cl^-]##=# #(2xx0.125*mol*cancelL^-1xx80xx10^-3cancelL)/(100xx10^-3L)#

#=# #??mol*L^-1#