# How do you solve #49x ^ { 2} - 56x + 15= 0#?

##### 1 Answer

May 28, 2017

#### Explanation:

Solve this quadratic equation methodically:

Use the new Transforming Method (Socratic, Google Search)

Transformed equation:

Proceeding: Find the 2 real roots of y', then, divide them by a = 49.

Find 2 real roots knowing sum (-b = 56) and product (ac = 735).

Compose factor pairs of (735) --> ...(5, 147)(7, 105)(21, 35).

This sum is (35 + 21 = 56 = -b). Therefore, the 2 real roots of y' are:

35, and 21. Back to original y, the 2 real roots are: