# Question #70c50

$M n {\left(C O\right)}_{5}$ is likely to act as an oxidizing agent.
$F e {\left(C O\right)}_{5}$ has eight valence electrons on the iron and the CO molecules each add two more through the sigma orbitals, so we get up to 18. $F {e}_{2} {\left(C O\right)}_{9}$ gets 18 electrons around both iron atoms by sharing a pair of electrons in a metal-metal bond, and similarly for $M {n}_{2} {\left(C O\right)}_{10}$. But with $M n {\left(C O\right)}_{5}$ can't get past 17 valence electrons (7 from the Mn, 10 from the CO molecules and no metal-metal bond) unless it takes one from something else. Hence -- an oxidizing agent.