Question #f0003

1 Answer
Ernest Z.
Feb 11, 2016

You must add 170 cal to melt the iron.

The formula for the heat required is

#q = mcΔT#

#ΔT = "1530 °C – 25 °C" = "1505 °C"#

Hence

#q= mcΔT = 1.0 color(red)(cancel(color(black)("g"))) × 0.11color(white)(l) "cal"·color(red)(cancel(color(black)("g"^(-1)"°C"^(-1)))) × 1505 color(red)(cancel(color(black)("°C"))) = "170 cal"# (2 significant figures)

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