see the video
reaction with C,S andP
reaction with Cu
Here's what I got.
As you know, nitric acid,
Now, when nitric acid reacts with non-metals, it oxidizes them to their highest oxidation state.
The difference between concentrated nitric acid and dilute nitric acid lies with the reduction of the acid.
As a rule of thumb, you'll often see mentions of how concentrated nitric acid is reduced to nitrogen dioxide,
The reduction of the acid depends on its concentration, so the more dilute the acid is, the greater its reduction. Depending on concentration and temperature, very dilute nitric acid will get reduced to nitrous oxide,
For your purposes, assume that the dilute nitric acid is concentrated enough to be reduced to nitric oxide,
So, when dilute nitric acid reacts with elemental carbon, it will oxidize carbon to its highest oxidation state, which is
The balanced chemical equation for this reaction is
#3"C"_text((s]) + 4"HNO"_text(3(aq]) -> 3"CO"_text(2(g]) + 4"NO"_text((g]) + 2"H"_2"O"_text((l])#
Notice that nitrogen is reduced from an oxidation state of
Sulfur and phosphorus will be oxidized to their highest oxoacids, i.e. acids in which they're in their highest oxidation state. Remember, you're working with dilute nitric acid, so look for it to be reduced to nitric oxide,
#"S"_text((s]) + 2"HNO"_text(3(aq]) -> "H"_2"SO"_text(4(aq]) + 2"NO"_text((g])#
Here sulfur goes from an oxidation state of
Now, I'm not really sure about dilute nitric acid oxidizing phosphorus to phosphoric acid. From what I remember, you needed concentrated nitric acid to do that, but I may very well be mistaken, so I'll skip this reaction.
I know that nitric acid can oxidize white phosphorus to phosphoric acid, but I'm not sure if the acid is concentrated or dilute
#"P"_text(4(s]) + 10"HNO"_text(3(aq]) + "H"_2"O"_text((l]) -> 4"H"_3"PO"_text(4(aq]) + 5"NO"_text((g]) + 5"NO"_text(2(g])#
Finally, dilute nitric acid will react with copper and be reduced to nitric oxide in the process
#3"Cu"_text((s]) + 8"HNO"_text(3(aq]) -> 3"Cu"("NO"_3)_text(2(aq]) + 4"NO"_text(2(g]) + 2"H"_2"O"_text((l])#