# Question #f34d1

Mar 8, 2016

a. $2.26$ $g$ ${N}_{2}$
b.$0.17$ $m o l$ $N {O}_{3}$
c. $48.0$ $g$ ${O}_{2}$

#### Explanation:

1. First, take all the molar masses of the elements/compound involved in the reactin;
2. Start solving the problem using dimensional analysis using the values provided in the problem and the molar masses you have just obtained.;
3. Make sure you have the right equivalence statement based on your computed molar masses and the ratio of the values;

For example you found:

$N {O}_{3}$ to be $62$ $g$/mol

The equivalence statement would be:

$62$ $g$ of $N {O}_{3}$ = $1$ mole of $N {O}_{3}$

The conversion factor would be the ratio of these 2 units and to discern which one is your numerator and denominator greatly lies on your desired unit. Conversion factor can be represented like these:

$\frac{1 m o l N {O}_{3}}{62 g N {O}_{3}}$

$\mathmr{and}$

$\frac{62 g N {O}_{3}}{1 m o l N {O}_{3}}$

1. You can do the same calculations as reflected above and please bear in mind to cancel out same units, leaving only your desired unit.