Question

Question #f34d1

Answer 1

a. `2.26` `g` `N_2`
b.`0.17` `mol` `NO_3`
c. `48.0` `g` `O_2`

Explanation:

1. First, take all the molar masses of the elements/compound involved in the reactin;
2. Start solving the problem using dimensional analysis using the values provided in the problem and the molar masses you have just obtained.;
3. Make sure you have the right equivalence statement based on your computed molar masses and the ratio of the values;

For example you found:

`NO_3` to be `62` `g`/mol

The equivalence statement would be:

`62` `g` of `NO_3` = `1` mole of `NO_3`

The conversion factor would be the ratio of these 2 units and to discern which one is your numerator and denominator greatly lies on your desired unit. Conversion factor can be represented like these:

`(1 mol NO_3)/(62 g NO_3)`

`or`

`(62 g NO_3)/(1 mol NO_3)`

1. You can do the same calculations as reflected above and please bear in mind to cancel out same units, leaving only your desired unit.