How do you graph the function #0 = x^2+6x+9# ?
2 Answers
See explanation...
Explanation:
The given expression:
#0 = x^2+6x+9#
is an equation, not a function.
We can express the related function as:
#f(x) = x^2+6x+9 = (x+3)^2#
In which case the given equation represents the zeros of the function, i.e. the intersections of
Note that for any real number
Hence:
#(x+3)^2 >= 0#
with equality if and only if
So what we have here is a parabola with vertex on the
To find the intersection with the
#f(0) = 0^2+6(0)+9 = 9#
That is:
We could evaluate
graph{x^2+6x+9 [-8, 3, -1.1, 10.2]}
graph{(x+3)^2 [-10, 10, -5, 5]}
Explanation:
This is in the form
We know
I.e.